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Home » x^3 - 4x^2 + 5x - 6 = 0 - Baxtercollege

x^3 - 4x^2 + 5x - 6 = 0 - Baxtercollege

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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🔥 Popular Posts

a contradiction. Hence, no real solution exists. The equation is undef...
Compute the sum of the roots of the equation \( u\sqrt{u} - 5u + 6\sqr...
Let \( v = \sqrt{u} \), so \( u = v^2 \). Substitute:
v^2 \cdot v - 5v^2 + 6v = 0 \quad \Rightarrow \quad v^3 - 5v^2 + 6v =...
v(v^2 - 5v + 6) = 0.
Factor quadratic:
v(v - 2)(v - 3) = 0.
So, \( v = 0, 2, 3 \). Since \( u = v^2 \), the corresponding roots ar...
All roots are non-negative, so valid.
Sum of roots: \( 0 + 4 + 9 = 13 \).

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