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Home » The final answer is $ \boxed2x^4 + 3x^2 - 1 $. - Baxtercollege

The final answer is $ \boxed2x^4 + 3x^2 - 1 $. - Baxtercollege

📅 March 11, 2026 👤 scraface

Mar 11, 2026

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\( 3x + 2y + 10x - 2y = 16 + 18 \),
\( 13x = 34 \),
\( x = \frac{34}{13} = \frac{34}{13} \).
Substitute \( x \) back into the first equation:
\( 3\left(\frac{34}{13}\right) + 2y = 16 \),
\( \frac{102}{13} + 2y = 16 \),
\( 2y = 16 - \frac{102}{13} = \frac{208}{13} - \frac{102}{13} = \frac{...
\( y = \frac{53}{13} \).
#### \( x = \frac{34}{13}, y = \frac{53}{13} \)1. **A cylindrical tank...
Substituting the given values: \( V = \pi \times 3^2 \times 5 = 45\pi...

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