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Home » The circumference of the containment field is $ \boxed17\pi $. - Baxtercollege

The circumference of the containment field is $ \boxed17\pi $. - Baxtercollege

📅 March 11, 2026 👤 scraface

Mar 11, 2026

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Volume of a cone: \( V = \frac{1}{3} \pi r^2 h \).
\( r = 3 \, \text{cm} \), \( h = 9 \, \text{cm} \).
\( r^2 = 9 \), so \( V = \frac{1}{3} \pi \times 9 \times 9 = \frac{1}{...
Using \( \pi \approx 3.14159 \), \( V \approx 27 \times 3.14159 = 84.8...
#### 84.82 cm³
Solve for \( x \): \( 2^{x+1} = 16^{x-1} \).
Express 16 as a power of 2: \( 16 = 2^4 \), so \( 16^{x-1} = (2^4)^{x-...
Equation becomes: \( 2^{x+1} = 2^{4x - 4} \).
Equate exponents: \( x + 1 = 4x - 4 \).
Solve: \( 1 + 4 = 4x - x \rightarrow 5 = 3x \rightarrow x = \frac{5}{3...

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