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Home » Simplify to \(31.4 = 6.28r\). - Baxtercollege

Simplify to \(31.4 = 6.28r\). - Baxtercollege

📅 March 11, 2026 👤 scraface

Mar 11, 2026

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+ (t^2 - 2) + 2t = t^2 + 2t + 1 = (t + 1)^2
Now, $ t = \tan x + \cot x \geq 2 $ by AM-GM, with equality when $ \ta...
So minimum occurs at $ t = 2 $, giving:
$$Question: A right triangular solar panel on a spacecraft has a hypot...
SQuestion: A quantum sensing device is positioned at the center of a s...
Solution: The area of the entire spherical tumor (modeled as a circle...
A_{\text{tumor}} = \pi \cdot 6^2 = 36\pi \text{ cm}^2
The area where the device is operational is a smaller circle of radius...
A_{\text{operational}} = \pi \cdot 3^2 = 9\pi \text{ cm}^2
The area where the device is **not** operational is the difference:

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Let \( N = 100a + 10b + 3 \). We require \( N \equiv 0 \pmod{9} \). Si...
N \equiv a + b + 3 \pmod{9}
We need:
a + b + 3 \equiv 0 \pmod{9} \quad \Rightarrow \quad a + b \equiv 6 \pm...
So \( a + b = 6 \) or \( a + b = 15 \) (since \( a \geq 1 \), \( b \le...
First, count solutions to \( a + b = 6 \), \( a \geq 1 \), \( b \geq 0...
\( a \) ranges from 1 to 6 → \( b = 6 - a \geq 0 \), so 6 solutions.
Now, \( a + b = 15 \):
\( a \geq 6 \) (since \( b \leq 9 \)), and \( a \leq 9 \). So \( a = 6...
\( a = 6 \), \( b = 9 \)

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