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Home » Prime Gaming Free Games Revealed: Top Picks You NEED to Try NOW! - Baxtercollege

Prime Gaming Free Games Revealed: Top Picks You NEED to Try NOW! - Baxtercollege

📅 March 11, 2026 👤 scraface

Mar 11, 2026

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📌 f(z) = \left(z + \frac{8}{3}\right)^3 - 8\left(z + \frac{8}{3}\right)^2 + 9\left(z + \frac{8}{3}\right) - 18.

📌 = z^3 + 3z^2\cdot\frac{8}{3} + 3z\cdot\frac{64}{9} + \frac{512}{27} - 8\left(z^2 + \frac{16}{3}z + \frac{64}{9}\right) + 9z + 24 - 18

📌 = z^3 + 8z^2 + 21.333z + 18.96 - 8z^2 - \frac{128}{3}z - \frac{512}{9} + 9z + 6

📌 Bessere Zahlen:

📌 \( \frac{8}{3} \), \( (\frac{8}{3})^2 = \frac{64}{9} \), \( (\frac{8}{3})^3 = \frac{512}{27} \)

📌 Jede Term:

📌 \( (z + \frac{8}{3})^3 = z^3 + 3\cdot\frac{8}{3}z^2 + 3\cdot\frac{64}{9}z + \frac{512}{27} = z^3 + 8z^2 + \frac{192}{9}z + \frac{512}{27} = z^3 + 8z^2 + \frac{64}{3}z + \frac{512}{27} \)

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+ 2y^2 = 2 \Rightarrow y^2 = 1 \Rightarrow y = \pm1 \Rightarrow z = \p...
So possible coordinates: $(0,1,1)$ or $(0,-1,-1)$.
Check distances:
From $(0,1,1)$ to $(0,0,0)$: $\sqrt{0 + 1 + 1} = \sqrt{2}$
To $(1,1,0)$: $\sqrt{1 + 0 + 1} = \sqrt{2}$
To $(1,0,1)$: $\sqrt{1 + 1 + 0} = \sqrt{2}$
All distances match.
Thus, the fourth vertex is $\boxed{(0,1,1)}$.
Question: Find all angles $z \in [0^\circ, 360^\circ]$ that satisfy
2\sin^2 z - 3\sin z + 1 = 0

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