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Home » Official results and minute reports published on AFC.tv and social media platforms. - Baxtercollege

Official results and minute reports published on AFC.tv and social media platforms. - Baxtercollege

📅 March 11, 2026 👤 scraface

Mar 11, 2026

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📌 10t + 6b = 86 \\

📌 10t + 25b = 155

📌 Subtract the first from the second:

📌 But since the problem likely expects integer values, we recheck:

📌 19b = 69 \Rightarrow b = \frac{69}{19}

📌 Wait — this suggests non-integer. Let's resolve with integer assumption. Try substitution.

📌 5t = 43 - 3b \Rightarrow t = \frac{43 - 3b}{5}

📌 Substitute into the second:

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Question: What two-digit positive integer is one more than a multiple...
Solution: Let $ x $ be the two-digit number. We are given:
x \equiv 1 \pmod{7}, \quad x \equiv 3 \pmod{5}
We solve this system using the Chinese Remainder Theorem.
Let $ x = 7k + 1 $. Substitute into the second congruence:
7k + 1 \equiv 3 \pmod{5} \Rightarrow 7k \equiv 2 \pmod{5} \Rightarrow...
So $ k = 5m + 1 $, and $ x = 7(5m + 1) + 1 = 35m + 8 $.
We now find a two-digit value of $ x $:
35m + 8 \geq 10 \Rightarrow m \geq 0, \quad 35m + 8 \leq 99 \Rightarro...
Try $ m = 0 $: $ x = 8 $ (not two-digit)

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