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Home » Inside True North VBS: The Most Unbelievable Comeback Ever! Watch Now! - Baxtercollege

Inside True North VBS: The Most Unbelievable Comeback Ever! Watch Now! - Baxtercollege

📅 March 11, 2026 👤 scraface

Mar 11, 2026

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📌 Try numerical: \( f(1) = (1 - 3)/(1 + 1) = -2/2 = -1 \), \( f(-1) = ((-1)^3 - 3(-1))/(1 + 1) = (-1 + 3)/2 = 1 \), so \( f(f(1)) = f(-1) = 1 = x \). So \( x = 1 \) is a solution.

📌 Similarly, \( f(-1) = 1 \), so \( f(f(-1)) = f(1) = -1 = x \), so \( x = -1 \) is a solution.

📌 So far: \( x = -1, 0, 1 \) are solutions.

📌 Now try \( x = 2 \): \( f(2) = (8 - 6)/(4 + 1) = 2/5 = 0.4 \), \( f(0.4) = (0.064 - 1.2)/(0.16 + 1) = (-1.136)/1.16 pprox -0.98 \), close to 1, not 2.

📌 But \( f(f(2)) pprox -1

📌 Try \( x = \sqrt{3} \): \( f(\sqrt{3}) = (3\sqrt{3} - 3\sqrt{3})/(3 + 1) = 0 \),

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\cdot rac{r^5 - 1}{r - 1} > 300
rac{r^5 - 1}{r - 1} > 100
We test integer values of $ r > 1 $ (since $ r = 1 $ gives $ S_5 = 15...
For $ r = 2 $:
rac{32 - 1}{2 - 1} = 31 \quad \Rightarrow \quad 3 \cdot 31 = 93 < 300
For $ r = 3 $:
rac{243 - 1}{3 - 1} = rac{242}{2} = 121 \quad \Rightarrow \quad 3 \cd...
Thus, $ r = 3 $ satisfies the condition, and since $ r = 2 $ does not,...
Question: A primatologist observes that the number of vocalizations a...
We compute the terms step-by-step using the recurrence $ v_n = 2v_{n-1...

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