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Home » But since question likely expects exact calculation: - Baxtercollege

But since question likely expects exact calculation: - Baxtercollege

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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\frac{1}{2} \times (b + 4) \times h'
\frac{1}{2} \times (b + 4) \times h' - 48
Assuming \(b = 8\) (from solving the quadratic equation derived from a...
h = \sqrt{100 - 16} = \sqrt{84} \approx 9.165
The new height \(h'\) becomes:
h' = \sqrt{100 - \frac{(8+4)^2}{4}} = \sqrt{100 - 36} = \sqrt{64} = 8
\frac{1}{2} \times 12 \times 8 = 48
- 48 = 0
Thus, the area does not increase, and the change is:
A right triangle has legs of lengths \(6 \, \text{cm}\) and \(8 \, \te...

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