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Home » \(A\) = configurations without I, - Baxtercollege

\(A\) = configurations without I, - Baxtercollege

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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The diagonal of the square is the diameter of the circumscribed circle...
d = \sqrt{5^2 + 5^2} = \sqrt{50} = 5\sqrt{2}
The radius \(r\) of the circle is half the diagonal:
r = \frac{5\sqrt{2}}{2}
C = 2\pi r = 2\pi \left(\frac{5\sqrt{2}}{2}\right) = 5\pi\sqrt{2}
Thus, the circumference of the circle is:
\boxed{5\pi\sqrt{2}}
Given a triangle with sides \(7 \, \text{cm}\), \(24 \, \text{cm}\), a...
The triangle is a right triangle (since \(7^2 + 24^2 = 25^2\)). The ar...
A = \frac{1}{2} \times 7 \times 24 = 84 \, \text{cm}^2

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