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Home » لذلك، أكبر قيمة ممكنة لـ $\gcd(a,b)$ هي $\boxed48$. - Baxtercollege

لذلك، أكبر قيمة ممكنة لـ $\gcd(a,b)$ هي $\boxed48$. - Baxtercollege

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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الإجابة النهائية:** الزوايا هي $\boxed{240^\circ}$ و $\boxed{300^\circ...
السؤال: أوجد المتجه $\mathbf{v}$ بحيث أن $\mathbf{v} \times \begin{pma...
الحل: ليكن $\mathbf{v} = \begin{pmatrix} v_1 \\ v_2 \\ v_3 \end{pmatri...
\mathbf{v} \times \begin{pmatrix} 1 \\ 0 \\ 0 \end{pmatrix} = \begin{p...
نحتاج إلى أنه يساوي $\begin{pmatrix} 0 \\ 3 \\ -2 \end{pmatrix}$, مما...
= 0 \\
v_3 = 3 \\
-v_2 = -2 \implies v_2 = 2
إذن، $\mathbf{v} = \begin{pmatrix} v_1 \\ 2 \\ 3 \end{pmatrix}$، حيث ي...
\mathbf{v} = \begin{pmatrix} 0 \\ 2 \\ 3 \end{pmatrix}

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